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What mass of sodium hydroxide pellets must be poured into a waste drum containing 20.0 L o 3.0 mol/L sulphuric acid to completely neutralize the waste acid solution? Write a balanced chemical equation for this reaction.

okay, so here is the work I already did

my balanced chemical equation:
NaOH(aq) + H2SO4(aq) = Na2SO4(aq) + H2O(aq)
I think all of these would be aqueous when I refer to my solubility rules but I'm afraid I'm messing things up and there should be a precipitate?

Mol H2SO4= C x V
= (3.0 mol/L)(20.0 L)
= 60 mol H2SO4

60 mol H2SO4 x (1 mol NaOH/ 1 mol H2SO4)
= 60 mol NaOH

molar mass of NaOH: 22.99 g/mol + 16.00 g/mol + 1.01 g/mol
= 40 g/mol

Mass NaOH= 60 mol NaOH x (40g/1 mol)
=2400 g

I don't understand why that number is so big when I thought I was doing the equation right.

Thank you so very much for taking time out of your day to help me, it's really appreciated :)

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2 answers
  1. Your equation is right and yes all are aq, There are no ppts.
    However, the equation is not balanced. You need a coefficient 2 for NaOH.
    Yes 60 mols H2SO4
    With the balanced equation that makes 120 mols NaOH
    Then redo your work from there. If everything else is ok that will make the final answer 4800 g NaOH needed.

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  2. Ohhh I see now. Thank you so much!

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