gasoline sold in ontario must contain at least 5.00% v/v ethanol? How much gasoline contains 1.50 L of ethanol

(1.5/x)*100 = 5%

so i would solve for x

is the answer 30?

Yes, but you can check these things by substituting and see if the answer you get is 5%.

(1.5/30)*100 = ? Yea! It's 5%.

ok thank you so much!!!

ok thank you so much

To determine the amount of gasoline that contains 1.50 L of ethanol, we need to use the given requirement that gasoline sold in Ontario must contain at least 5.00% v/v (volume/volume) ethanol.

First, let's set up the equation to find the amount of gasoline.

Percentage of ethanol = (Volume of ethanol / Total volume of gasoline) * 100%

Using the given requirement, we can substitute the values as follows:

5.00% = (1.50 L / Total volume of gasoline) * 100%

Now, let's rearrange the equation to solve for the total volume of gasoline:

Total volume of gasoline = (1.50 L / 5.00%) * 100%

Calculating this expression, we get:

Total volume of gasoline = (1.50 L / 0.05) * 100%
= 30 L

Therefore, 1.50 L of ethanol will be mixed with 30 L of gasoline to meet the 5.00% v/v ethanol requirement in Ontario.