A ball is thrown upwards with an initial velocity of 16 m/s. What is the velocity of the ball 1.5 s later?

After the ball leaves the hand of the thrower, what is the value of acceleration acting on the ball as it is rising upwards?

9.8x1.5 = 14.7. 16-14.7=1.3 m/s after 1.5s.
The value of acceleration acting on the ball is -9.8 m/s, due to gravity.

Is this correct?

V = Vo + g*t = 16 - 9.8*1.5 = 1.3 m/s.

Your answers are correct.

Well, you're partially correct! The velocity of the ball 1.5 seconds later would be -3.5 m/s (instead of 1.3 m/s). This is because when the ball is thrown upwards, it experiences a downward acceleration due to gravity, which causes its velocity to decrease. As for the value of acceleration acting on the ball as it is rising upwards, you got it right! The acceleration would be -9.8 m/s² (negative because it is pointing in the opposite direction of motion). Keep up the good work!

Yes, that is correct. The velocity of the ball 1.5 seconds later is 1.3 m/s and the value of acceleration acting on the ball as it is rising upwards is -9.8 m/s², which is the acceleration due to gravity.

The calculation for the velocity of the ball 1.5 seconds later seems to be incorrect. To determine the velocity of the ball at a specific time, it is necessary to consider the effects of gravity on the object.

To calculate the velocity, you need to break down the problem into two separate scenarios: when the ball is moving upward and when it is moving downward.

First, let's calculate the time it takes for the ball to reach its peak height. The equation to determine the time of flight is given by:

time = (final velocity - initial velocity) / acceleration

Here, the initial velocity is 16 m/s, the final velocity will be 0 m/s (as the ball reaches its peak height, it momentarily stops), and the acceleration is -9.8 m/s^2 (negative because it acts in the opposite direction of the initial velocity). Plugging in these values:

time = (0 - 16) / -9.8

Solving for time, we find:

time = 1.63 seconds

Now that we have the time it takes for the ball to reach its peak height, we can determine the velocity after 1.5 seconds.

For the first part of the motion (upward), we know the initial velocity is 16 m/s and the acceleration is -9.8 m/s^2. Using the equation:

velocity = initial velocity + (acceleration * time)

Plugging in the values:

velocity = 16 + (-9.8 * 1.5)

Solving for velocity, we get:

velocity = 16 + (-14.7) = 1.3 m/s

So, the velocity of the ball 1.5 seconds later is 1.3 m/s.

Regarding the value of acceleration acting on the ball as it is rising upward, it is indeed -9.8 m/s^2. The negative sign indicates that the velocity is decreasing as the ball moves against the direction of gravity.