degree 4

zeros i & (1+i)
constant term 12

How do I start this problem.

Thanks

A degree four polynomial will have the form (x^4 +... x + c), where c is a constant. You will need to generate an equation that has the above form, using c=12. Solve for the roots [i & (1+i)].

1 answer

  1. The equation would be:

    x^4 + ax^3 + bx^2 + cx + 12 = 0

    To solve for the coefficients a, b, and c, you can use the following equations:

    a = -(i + (1+i))
    b = i(1+i)
    c = -12

    Therefore, the polynomial is:

    x^4 - (i + (1+i))x^3 + i(1+i)x^2 - 12x + 12 = 0

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