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Water flowing through a 1.9-cm-diameter pipe can fill a 500L bathtub in 5.1min. What is the speed of the water in the pipe?

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8 answers
  1. area of pipe * speed of water = Q = flow volume/second

    area = pi (.019)^2

    volume = 0.5 m^3
    time = 5.1*60 = 306
    so

    pi (.019)^2 V = .5 m^3/306 s
    solve for V in m/s

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  2. I did:
    Q=change in v/change in t

    = (500L)/(5.1m)
    = (500L)/ (306s)
    = 1.6 L/s

    convert > 1 L = 100 mL = 10^3 cm^3 = 10^-3 m^3... therefore I got 16 x 10^-4

    v= Q/A = Q/(pi)(r^2)
    v = 16x10^-4/(pi)(0.0955)^2
    = 0.017

    i am incorrect though

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  3. I get 1.45 m/s

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  4. Re-tried using your help...

    (pi)(0.19^2)V= 0.5m^3/306s

    (pi)(0.19^2)V= 0.016

    V= 0.016/(pi)(0.19^2)

    V= 8 x 10^-4

    ... i was incorrect

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  5. whoops I used diameter
    use 4*1.45 = 5.8 m/s

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  6. .5/306 = .00163, not .0163

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  7. r = .019/2 = .0095
    you have a decimal point off in the diameter too

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  8. Just follow my way using the diameter and multiply by 4 at the end. A = pi d^2/4

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