The color of light emitted by a hot solid object depends on?

The color of light emitted by a hot solid object depends on its temperature. This is explained by a concept called blackbody radiation, which describes the emission of electromagnetic radiation by an idealized object that absorbs all radiation incident upon it.

The relationship between the temperature of a hot solid object and the color of light it emits can be determined using Planck's law. According to this law, the intensity and distribution of light emitted by a blackbody is a function of its temperature.

To calculate the color of light emitted by a hot solid object, you can use Wien's displacement law. This law states that the wavelength at which the intensity of light emitted by a blackbody is maximum (known as peak wavelength or lambda max) is inversely proportional to its temperature. Mathematically, Wien's displacement law can be expressed as lambda max = b / T, where lambda max is the peak wavelength, T is the temperature in Kelvin, and b is Wien's displacement constant.

The color associated with a particular wavelength can be determined using the electromagnetic spectrum. The visible light portion of the electromagnetic spectrum ranges from approximately 400 to 700 nanometers. Shorter wavelengths correspond to higher frequency light, which is perceived as violet or blue, while longer wavelengths correspond to lower frequency light, which is perceived as red.

By applying Wien's displacement law and understanding the relationship between wavelength and color, you can determine the color of light emitted by a hot solid object based on its temperature. The higher the temperature, the shorter the wavelength (towards the blue end of the spectrum), while lower temperatures result in longer wavelengths (towards the red end of the spectrum).