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The acceleration of gravity is 9.8 m/s^2 . What is the magnitude of the total force on a(n) 72 kg driver by the dragster he operates as it accelerates horizontally along a straight line from rest to 61 m/s in 7.8 s? Answer in units of kN

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4 answers
  1. total force? that is weight, plus horizontal force.

    weight: 72*9.8 N
    horizontal force= 72*(61/7.8) N

    magnitude then= sqrt (weight^2+horizonal^2)

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    bobpursley
  2. F=m*a

    It only asks about the force from the dragster, so ignore gravity. F = 72*a

    a = (Vf-Vo)/t

    a=61/7.8

    F = (72)(71/7.8)

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  3. I would like to agree, but there is a force from the table on the dragster wupward supporting weight, so it can go horizonatally.....

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    bobpursley
  4. Vinny I'm sorry to do this to someone who shares my name but bob is right ;3

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