A box,is resting on a smooth(frictionless)table.The mass of the box is 10 kg. (a)Determine the weight of the box and the normal force acting on(b)If the box is pushed down with a force of 40 Newton determine the normal force(c) If the box was pulled up with a force of 40 Newton,what now is the normal force on the box?
I know the question is long but I would greatly appreciate it if you solved it ..thank you!!!
(a) The weight is M g = 98 N.
(b) If you push down with 40 N force, add that to the weight
(c) If you pull up with a 40N force, subtract that from the weight.
Dear student,
Oh lol don't worry about this being long i delt with more :)
okay now lets understand that i cant give answers but my explanations...i might as well tell you the answer LO xD now Drwls said (a) The weight is M g = 98 N.
(b) If you push down with 40 N force, add that to the weight
(c) If you pull up with a 40N force, subtract that from the weight. Correct i would say that too BUT... theirs a ALOT SIMPLE WAY FAS (force,add,subb
Eevee,
p.s need more help?
Oh, no worries! I'm happy to help with your question. Let's get started with the weight and normal force calculations for the box.
(a) The weight of the box can be determined by multiplying the mass (10 kg) by the acceleration due to gravity, which is approximately 9.8 m/s^2. So, the weight of the box is 10 kg * 9.8 m/s^2 = 98 Newtons.
Since the box is resting on a smooth table, there is no upward force resisting the weight of the box. Therefore, the normal force acting on the box is equal to the weight of the box, which is 98 Newtons.
(b) If the box is now being pushed down with a force of 40 Newtons, we need to consider the net force acting on the box. The net force is the difference between the applied force and the weight of the box. In this case, the net force is 40 N - 98 N = -58 N (negative because it opposes the upward direction).
The negative net force causes the box to accelerate upward, but since the box cannot move due to the smooth table, the normal force must increase to balance the net force. Therefore, the normal force in this situation would be greater than the weight of the box, which is 98 Newtons.
(c) Now, if the box is pulled up with a force of 40 Newtons, we again calculate the net force as the difference between the applied force and the weight of the box. The net force is 40 N - 98 N = -58 N.
This time, the negative net force causes the box to accelerate downward, but it can't move due to the smooth table. So, the normal force must decrease to balance the net force. Therefore, the normal force in this situation would be less than the weight of the box, which is 98 Newtons.
I hope that helps! If you have any more questions or need a dose of humor, feel free to ask!
Sure, I can help you with that!
(a) To determine the weight of the box and the normal force acting on it, we need to understand the basic principles of forces and Newton's second law.
The weight of an object can be calculated using the formula:
Weight = mass * acceleration due to gravity
The acceleration due to gravity on Earth is approximately 9.8 m/s^2. So, in this case, the weight of the box would be:
Weight = 10 kg * 9.8 m/s^2 = 98 N
Since the box is resting on a smooth table, there is no vertical acceleration acting on it. Therefore, the normal force acting on the box would be equal in magnitude and opposite in direction to the weight. So, the normal force would also be 98 N.
(b) If the box is pushed down with a force of 40 Newton, we need to consider the equilibrium of forces in the vertical direction. Since the box is not accelerating vertically, the net force in the vertical direction must be zero.
The net force in the vertical direction can be calculated by subtracting the force applied from the weight:
Net Force = Weight - Force applied = 98 N - 40 N = 58 N
Since the net force in the vertical direction is zero, the normal force must be equal in magnitude to the net force. So, the normal force would be:
Normal Force = 58 N
(c) If the box is pulled up with a force of 40 Newton, the same equilibrium principle applies. The net force in the vertical direction must be zero.
The net force in the vertical direction can be calculated by adding the force applied to the weight:
Net Force = Weight + Force applied = 98 N + 40 N = 138 N
Since the net force in the vertical direction is zero, the normal force must be equal in magnitude to the net force. So, the normal force would be:
Normal Force = 138 N
I hope this helps you understand how to solve these types of problems!