You have a tanker that is filled with olive oil, which total mass = 200 kg. The tanker is in the shape of a rectangular box w/vertical sides and a horizontal cross-sectional area 0.9 m^2. How deep a swimming pool do you need so that the tanker doesn't hit the bottom?

Wondering what the empty tanker weights?

olive oil mass=200kg
olive oil volume= 200kg/densityOO

water displaced volume= 200kg/densityWT

volume=height*area

height=200kg/(densityWT*.9)
height=200/1040*.9= you do it. This is the depth of water needed to hold 200kg floating

To determine the depth of the swimming pool needed so that the tanker doesn't hit the bottom, we need to consider the buoyant force acting on the tanker.

The buoyant force is the upward force exerted on the tanker by the fluid (olive oil) it is submerged in. It is equal to the weight of the fluid displaced by the submerged object.

In this case, the buoyant force is equal to the weight of the olive oil in the tanker. To calculate this:

Step 1: Calculate the volume of the olive oil in the tanker.
Volume = horizontal cross-sectional area × depth
Volume = 0.9 m^2 × depth

Step 2: Convert the volume to mass using the density of olive oil.
The density of olive oil is typically around 900 kg/m^3.

Mass of olive oil = Density × Volume
Mass of olive oil = 900 kg/m^3 × (0.9 m^2 × depth)

Given that the total mass of the olive oil in the tanker is 200 kg, we can set up the equation:

Mass of olive oil = 200 kg

900 kg/m^3 × (0.9 m^2 × depth) = 200 kg

Step 3: Solve for depth.
0.9 m^2 × depth = 200 kg / (900 kg/m^3)
0.9 m^2 × depth = 0.222 m^3
depth = 0.222 m^3 / 0.9 m^2
depth ≈ 0.247 m

Therefore, the swimming pool should be at least 0.247 meters (or approximately 24.7 centimeters) deep for the tanker to not hit the bottom.