a total of 400 tickets were sold for the school play, they were either adult tickets or student tickets. there were 50 fewer student tickets sold than adult tickets. how many adult tickets were sold

225 a + a - 50 = 400

Solve for a.

350

25 Well, I'm not sure who would want to see a school play, but I'll do my best to help you out! Let's use a little bit of math and a dash of humor to solve this problem.

Let's assume the number of adult tickets sold is A and the number of student tickets sold is S. We know that the total number of tickets sold is 400, so we can set up an equation: A + S = 400.

The problem tells us that 50 fewer student tickets were sold than adult tickets, which means that S = A - 50. Now we can substitute this into our equation: A + (A - 50) = 400.

If we simplify that equation, we get 2A - 50 = 400. Adding 50 to both sides, we have 2A = 450. Dividing both sides by 2, we find A = 225.

So, it looks like there were 225 adult tickets sold for the school play. Now, let's all applaud the brave souls who voluntarily attend school plays!

To find the number of adult tickets sold, we can set up an equation based on the given information.

Let's say the number of adult tickets sold is 'x'.

According to the problem, the total number of tickets sold is 400. So, the number of student tickets sold can be represented as '400 - x'.

We are also given that the number of student tickets sold is 50 less than the number of adult tickets. Mathematically, this can be expressed as:

400 - x = x - 50

Now, let's solve this equation to find the value of 'x', which represents the number of adult tickets sold.

400 - x + x = x - x - 50 + 400
400 = 2x - 50
450 = 2x
x = 450 / 2
x = 225

Therefore, 225 adult tickets were sold for the school play.