Assuming equal concentrations and complete dissociation, rank these aqueous solutions by their freezing points: Li2SO4 K3PO4 LiNO3

LiNo3>Li2SO4>K3PO4

To rank the aqueous solutions by their freezing points, we need to consider the number of particles that each solute dissociates into when it is dissolved in water. The more particles present, the lower the freezing point.

1. K3PO4:
K3PO4 dissociates into 4 particles in water: 3 K+ ions and 1 PO4 3- ion.

2. Li2SO4:
Li2SO4 dissociates into 3 particles in water: 2 Li+ ions and 1 SO4 2- ion.

3. LiNO3:
LiNO3 dissociates into 2 particles in water: 1 Li+ ion and 1 NO3- ion.

Based on the above information, we can rank the aqueous solutions by their freezing points as follows:

1. LiNO3: It has the highest freezing point because it only dissociates into two particles in water.
2. Li2SO4: It has a slightly lower freezing point than LiNO3 because it dissociates into three particles in water.
3. K3PO4: It has the lowest freezing point among the three solutions because it dissociates into four particles in water.

Therefore, the ranking from highest to lowest freezing points is: LiNO3, Li2SO4, K3PO4.

To rank these aqueous solutions by their freezing points, we need to consider the number of particles the solute dissociates into when it dissolves in water. The greater the number of particles, the lower the freezing point of the solution.

Li2SO4 dissociates into three ions: 2 Li+ ions and 1 SO4^2- ion.
K3PO4 dissociates into four ions: 3 K+ ions and 1 PO4^3- ion.
LiNO3 dissociates into two ions: 1 Li+ ion and 1 NO3^- ion.

Since K3PO4 dissociates into the highest number of ions, it will have the lowest freezing point. Li2SO4 will have the second lowest freezing point because it dissociates into three ions, and LiNO3, which dissociates into the lowest number of ions, will have the highest freezing point.

So, based on their dissociation behavior, we can rank the aqueous solutions from lowest to highest freezing point as follows:

K3PO4 < Li2SO4 < LiNO3

delta T = i*Kf*m

So if Kf is he same and m is the same you can forget about K and m. Differences will be due only to i. i is the van't Hoff factor and
i = # particles on dissociation; e.g., LiNO3 will be 2 and that will have the highest freezing point of the three listed. Do you know i for the others?