How many tons of zinc can be obtained from 976 tons of zinc ore that is 78.0% zinc carbonate?

The easy. I just didn't go through the mopls steps.

976 tons ZnCO3 x 0.78 = approx 750 tons ZnCO3

750 tons ZnCO3 x (atomic mass Zn/molar mass ZnCO3) = ? tons Zn metal.

To determine the amount of zinc that can be obtained from the zinc ore, we need to calculate the actual weight of zinc in the ore.

First, we calculate the weight of zinc carbonate in the zinc ore:
Weight of zinc carbonate = 976 tons * (78.0% / 100) = 760.8 tons

Next, we calculate the weight of pure zinc in the zinc carbonate:
Weight of pure zinc = 760.8 tons * (100 / 222.9) = 3.41 tons

Therefore, approximately 3.41 tons of zinc can be obtained from 976 tons of zinc ore that is 78.0% zinc carbonate.

To calculate the amount of zinc that can be obtained from zinc ore, we need to find the percentage of zinc in the ore.

The zinc ore contains 78.0% zinc carbonate. This means that in 100 tons (100%) of the ore, there are 78.0 tons of zinc carbonate.

To find the amount of zinc in 976 tons of zinc ore, we can set up a proportion:

(78.0 tons zinc carbonate / 100 tons ore) = (X tons zinc / 976 tons ore)

Cross-multiplying, we get:

78.0 tons * 976 tons = 100 tons * X tons

Simplifying further:

76,128 tons = 100X

Dividing both sides of the equation by 100:

76,128 tons / 100 = X

X = 761.28 tons

Therefore, from 976 tons of zinc ore that is 78.0% zinc carbonate, we can obtain 761.28 tons of zinc.