Hello,
- 👍
- 👎
- 👁
- ℹ️
- 🚩
-
- 👍
- 👎
- ℹ️
- 🚩
Answer this Question
Similar Questions
-
Math
Find the value of b, if any, that will make the function differentiable at x = 0 g(x)= { x+b, x
-
Another algebra
Determine the number of positive integers n that satisfy: 1/2 < n/n+1 < 99/101 I don't know how to solve this besides plugging in random numbers, which would take all day. Any other suggestions for a faster way to solve it? Thank you!
-
math
Determine the end behavior of the function as x → +∞ and as x → −∞. f(x) = 1000 − 39x + 51x^2 − 10x^3 As x → +∞, f(x) → ???? . As x → −∞, f(x) → ??? I know that the end behavior of the function is determined by the leading
-
Calculus (Related Rates)
The position of a particle moving in a straight line is given by s(t) = (e^(-t))(cos(5t)) for t>0, where t is in seconds. If the particle changes direction at time T seconds, then T must satisfy the equation: cos(5T) = 0 5T = arctan(-1/5) 5e^(-t) sin(5t) =
-
Maths
the complete solution set of x which satisfy the inequality [4/(x-2) ]>=[3/(2x-1)]
-
Math
Explain how to write a function rule from the table below. Then write a function rule. x 2 4 6 y 1 0 –1 I don't get these Please help.
-
MAT222
-x+2y=-2 x-2y=2 the system has no solution the system has a unique solution: the system has infinitely many solutions. they must satisfy the following equation: y= the answer is the system has infinitely many solutions. i just don't understand how to get
-
Calculus
For the function f(x) = x^2 - 4x +5, x>= 2, which is equal to d/dx (f-1 this is the inverse)(x)) ? 1/(2y-4) where x and y are related by the equation (satisfy the equation) x=y^2-4y+5 x>= 1 2y-4 where x and y are related by the equation y= = x^2 - 4x +5,
-
Calc AB
Suppose that y = f(x) = x^2-4x+4 Then on any interval where the inverse function y = f^–1(x) exists, the derivative of y = f^–1(x) with respect to x is: a) 1/(2x-4) b) 1/(2y-4), where x and y satisfy the equation y=x^2-4x+4 c)(1/2)x^(-1/2)
-
algeBRA
How many integer values x satisfy the inequality 2
Still need help?
You can ask a new question or browse existing questions.