The solubility of sodium chloride (NaCl) was determined experimentally to be 35.7 g/ 100 g of water (H2O) at 200 C. How many grams of NaCl would dissolve in 50g of H2O at 200 C?

35.7 g x 50/100 = ?

17.85g of NaCl

To determine the number of grams of NaCl that would dissolve in 50g of H2O at 200°C, we can use a proportion based on the given solubility data.

The solubility of NaCl is given as 35.7 g/100 g of H2O at 200°C. This means that 100 g of water can dissolve 35.7 g of NaCl.

To find out how many grams of NaCl would dissolve in 50 g of water, we can set up a proportion:

(35.7 g NaCl) / (100 g H2O) = (x g NaCl) / (50 g H2O)

Now, we can cross-multiply and solve for 'x':

(35.7 g NaCl) * (50 g H2O) = (100 g H2O) * (x g NaCl)

1785 g NaCl = 100 g H2O * x

To isolate 'x', we divide both sides of the equation by 100 g H2O:

(1785 g NaCl) / (100 g H2O) = x

x = 17.85 g NaCl

Therefore, 17.85 grams of NaCl would dissolve in 50 grams of H2O at 200°C.