If f(x)=sqrt (x^24) and g(x)=3x2, then the derivative of f(g(x)) at x=3 is
A. 7/sqrt 5
B. 14/sqrt 5
C. 18/sqrt 5
D. 15/sqrt 21
E. 30/sqrt 21
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1 answer

df/dx = df/dg * dg/dx
= g/√(g^24) * (3)
= 3(3x2)/√((3x2)^24)
= 3(3x2)/√(9x^212x)
at x=3, that's
3(7)/√45
= 21 / 3√5
= 7/√5 👍
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answered by Steve
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