2t + 8 'greater than/equal to' -4(t+1)
t is 'greater than/equal to' ?_____?
i have an idea as to what the answer is but im pretty sure its wrong
can someone pls help me? thx
2t + 8 >= -4(t + 1)
2t + 8 >=-4t - 4
6t >= -12
t >= -2
**2t + 8 >= -4(t + 1)**
multiply negative 4 to both of the numbers in the parenthesis
**2t + 8 >=-4t - 4**
negate 8 on both sides
**2t>=-4t-12**
add 4t on both sides
**6t >= -12**
divide by 6
6t/6=1t=t
-12/6=-2
**t >= -2**
Sure, I'd be happy to help you out with this equation in a humorous way!
Let's solve it step by step and see if we can find the answer that will make you giggle.
First, let's distribute -4 to both t and 1:
2t + 8 ≥ -4t - 4
Now, let's combine like terms:
2t + 4t ≥ -4 - 8
Next, let's simplify:
6t ≥ -12
To solve for t, we need to isolate it. But before we do that, let's have a little laugh while we wait.
Why don't scientists trust atoms?
Because they make up everything!
Alright, back to business. Let's divide both sides of the equation by 6:
t ≥ -2
And there you have it, the answer is t ≥ -2! I hope this helps and puts a smile on your face. If you have any more questions, feel free to ask!
To solve the inequality 2t + 8 ≥ -4(t+1), we can start by simplifying it:
Distribute -4 to (t+1):
2t + 8 ≥ -4t - 4
Combine like terms:
2t + 4t + 8 ≥ -4
6t + 8 ≥ -4
Subtract 8 from both sides to isolate the variable:
6t ≥ -4 - 8
6t ≥ -12
Now, we can solve for t by dividing both sides of the inequality by 6:
t ≥ -12/6
t ≥ -2
So the solution for the inequality 2t + 8 ≥ -4(t+1) is t ≥ -2.
To solve the inequality 2t + 8 ≥ -4(t + 1), you need to apply the following steps:
1. Distribute the -4 to both terms inside the parentheses:
2t + 8 ≥ -4t - 4.
2. Combine like terms by adding 4t to both sides:
2t + 4t + 8 ≥ -4t + 4t - 4.
6t + 8 ≥ 0.
3. Subtract 8 from both sides to isolate the t term:
6t + 8 - 8 ≥ 0 - 8.
6t ≥ -8.
4. Finally, divide both sides by 6 to solve for t:
(6t)/6 ≥ (-8)/6.
t ≥ -4/3.
Therefore, the solution to the inequality 2t + 8 ≥ -4(t + 1) is t ≥ -4/3.