A bank lent $260,000 to a company for development of two products. If the loan for product A was for $77,000 more than that for product B, how much was lent for each product?

A + B = 260,000

A = B + 77,000
so

B + 77,000 + B = 260,000
or
2 B = 183,000
etc

B + B + 77,000 = 260,000

2B = 183,000

B = 915,000

B = 91,500

I really appreciate the help Ms. Sue and Damon

You're very welcome.

To solve this problem, we can set up a system of equations and solve them simultaneously.

Let's assume that the loan for product B is x dollars. According to the problem, the loan for product A is $77,000 more than the loan for product B. So, the loan for product A can be represented as (x + $77,000).

Now, we know that the total loan amount is $260,000. So we can write the equation:

x + (x + $77,000) = $260,000

Now, we can simplify the equation:

2x + $77,000 = $260,000

Subtract $77,000 from both sides of the equation:

2x = $260,000 - $77,000

2x = $183,000

Divide both sides of the equation by 2:

x = $183,000 / 2

x = $91,500

Therefore, the loan for product B is $91,500. Since the loan for product A is $77,000 more than that for product B, the loan for product A is:

$91,500 + $77,000 = $168,500

So, the bank lent $91,500 for product B, and $168,500 for product A.