Helpp needed, this is sort of confusing me.
Describe the nature of the roots for this equation.
2x^2-x+1=0
A. Two real, rational roots
B. Two real, irrational roots
C. One real, double root
D. Two complex roots
i have no idea
sorry, i tryed
typo, tried
nvmnd, it's D
thanks!!
To determine the nature of the roots of the quadratic equation 2x^2 - x + 1 = 0, we can use the discriminant formula. The discriminant is given by the expression b^2 - 4ac, where a, b, and c are the coefficients of the quadratic equation ax^2 + bx + c = 0.
In this case, a = 2, b = -1, and c = 1. So, the discriminant is calculated as follows:
Discriminant = (-1)^2 - 4 * 2 * 1
Discriminant = 1 - 8
Discriminant = -7
Since the discriminant is negative (-7), there are no real roots for this quadratic equation. Instead, there are two complex roots. Therefore, the correct answer is option D.