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Two particles are moving in straight lines. The displacement (meters) of particle 1 is given by the function s(t)= cos(4x), where t is in seconds. The displacement (meters) of particle 2 is given by the function s(t)= t^3/3-t^2/2 +2(t) , where t is in seconds. Find the first positive time at which the particles have the same velocity.

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2 answers
  1. you want where s' is the same for both particles

    -4sin(4x) = x^2-x+2

    Better use a graphing utility of numeric method. See

    http://www.wolframalpha.com/input/?i=-4sin%284x%29+%3D+x^2-x%2B2

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  2. Thanks :)

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