A man pushes a stalled car with a horizontal force of 312 N. The car does not move. What is the frictional drag force on the car?

A water-skier (mass=60kg) is pulled by a boat with a horizontal force of 300N. The boat and the skier have a constant velocity. What is the frictional drag force on the skier?

Oh, it looks like these questions are all about frictional forces. Well, friction can be a real drag sometimes! Let's see if I can help you out with some humorous answers:

For the first question, if the man is pushing with a force of 312 N and the car isn't budging, we can conclude that the frictional drag force must be pretty strong. Maybe the car just wants to take a little break and enjoy the scenery. Who can blame it?

And for the water-skier, if the boat and skier are moving at a constant velocity with a force of 300 N, that means the frictional drag force on the skier must be equal to the force applied. It's like the skier is hanging on for dear life, gripping on to the water for that wild ride. Hang on tight!

Remember, these answers are just for fun. If you need the actual calculations, I recommend consulting a physics textbook or a knowledgeable human.

To find the frictional drag force on the car and the skier, we can first calculate the net force acting on each of them.

For the car, since it does not move, the net force acting on it is zero. The force that the man applies to push the car horizontally is 312 N. So, the frictional drag force opposing the motion of the car must also be 312 N.

For the skier, since the boat and the skier have a constant velocity, it means that the net force acting on the skier is zero. The force applied by the boat to pull the skier horizontally is 300 N. Therefore, the frictional drag force opposing the motion of the skier must also be 300 N.

In both cases, the frictional drag force is equal to the force applied to move the object, since the net force is zero.

To calculate the frictional drag force on an object, we can use the equation:

Frictional Force = Applied Force - Net Force

Let's break down the steps to find the frictional drag force for each scenario:

1. A man pushing a stalled car:
In this case, the car does not move, indicating that the applied force is equal to the frictional drag force. Therefore, the frictional drag force on the car is 312 N.

2. Water-skier being pulled by a boat:
Since the boat and the skier have a constant velocity, it means there is no acceleration, and the net force is zero. Therefore, the applied force is equal to the frictional drag force. The applied force is given as 300 N, so the frictional drag force on the skier is also 300 N.

In both scenarios, if the object is not moving or has a constant velocity, the applied force would be equal to the frictional drag force.