How many grams of NaOH are contained in 5.0 × 102 mL of a 0.77 M sodium hydroxide solution? The molar mass of NaOH is

40.0 g/mol.

grams = M x L x molar mass

Use this online calculator

calistry. org/molarityCalculator

Well, to find out the grams of NaOH, we need to use some chemistry math. Now, I hope you're ready to get into some "heavy" calculations! *cue drum roll*

First, we need to calculate the moles of NaOH in the solution. To do that, we multiply the volume (in liters) by the concentration (in moles per liter).

So, in this case, we have:
Volume = 5.0 × 10² mL = 0.5 L (since 1000 mL = 1 L)
Concentration = 0.77 M

Okay, let's do some math now. Multiplying the volume and concentration gives us:

0.5 L x 0.77 mol/L = 0.385 moles of NaOH

Now that we have the moles, we'll need to convert them to grams using the molar mass of NaOH (40.0 g/mol).

0.385 moles x 40.0 g/mol = 15.4 grams of NaOH

So, voila! There are approximately 15.4 grams of NaOH in 5.0 × 10² mL of that solution. Keep in mind, though, this answer is as accurate as my clown makeup! *wink*

To find the number of grams of NaOH in the solution, we can use the formula:

grams of NaOH = (volume of solution in liters) × (concentration of NaOH in M) × (molar mass of NaOH)

First, we need to convert the volume of the solution from mL to liters:

volume of solution in liters = 5.0 × 10^2 mL ÷ 1000
= 0.5 L

Now, we can substitute the values into the formula:

grams of NaOH = (0.5 L) × (0.77 M) × (40.0 g/mol)

grams of NaOH = 15.4 g

Therefore, there are 15.4 grams of NaOH in 5.0 × 10^2 mL of a 0.77 M sodium hydroxide solution.

To determine the number of grams of NaOH in the given solution, you'll need to use the formula:

Mass of NaOH = Volume of Solution (in L) × Molarity of NaOH × Molar Mass of NaOH

First, convert the volume of the solution from milliliters (mL) to liters (L):

5.0 × 10^2 mL = 5.0 × 10^2 / 1000 L
= 0.50 L

Next, substitute the given values into the formula:

Mass of NaOH = 0.50 L × 0.77 M × 40.0 g/mol

Now, calculate the mass of NaOH:

Mass of NaOH = 0.50 L × 0.77 M × 40.0 g/mol
= 15.4 g

Therefore, there are 15.4 grams of NaOH in 5.0 × 10^2 mL of a 0.77 M sodium hydroxide solution.