# What volume of H2O should be added to 500 ML of a 1.0 mol/L CuSO4 solution to dilute it to 0.5 mol/L?

This is what I have so far...

H20 + CuSO4 --------> H2SO4 + CuO

So you use the formula M1V1 = M2V2

so its (0.500)(1.0) = (0.5)(V)

Solve for V, I got 1.0 L.

HOWEVER, the answer is supposed to be 500 ML. Could someone please correct my work?

Thank you in advance!!

YOu want to dilute it by a factor of 2? Add one part water to one part acid.

I am not into formulas. However, as a special to you, the volume you got was right...but you solved for the volume of the new acid. Remember, that volume is the volume of the water and the original acid.

Why don't you just do it my way?

If you want to dilute something by a factor of three, add two parts water to one part of the original solution. And so on.

I don't really understand what you mean by "factors"... factors of 2 and factors of 3?