Write a balanced chemical equation for the reaction of solid vanadium(V)({\rm V}) oxide with hydrogen gas to form solid vanadium(III)({\rm III}) oxide and liquid water.
V2O5 + 2H2 ==> V2O3 + 2H2O
The balanced chemical equation for the reaction of solid vanadium(V) oxide with hydrogen gas to form solid vanadium(III) oxide and liquid water is:
V2O5 + 5H2 → 2V2O3 + 5H2O
To write a balanced chemical equation, we need to follow a few steps:
Step 1: Identify the chemical formula of the reactants and products.
In this case, the reactants are solid vanadium(V) oxide (V2O5) and hydrogen gas (H2). The products are solid vanadium(III) oxide (V2O3) and liquid water (H2O).
Step 2: Write the unbalanced equation.
Based on the identified reactants and products, we can write the unbalanced equation as follows:
V2O5 + H2 -> V2O3 + H2O
Step 3: Balance the equation by adding coefficients in front of the chemical formulas.
In this step, we need to balance the numbers of atoms on both sides of the equation. Let's start by balancing the vanadium atoms:
V2O5 + H2 -> 2V2O3 + H2O
Next, balance the oxygen atoms:
V2O5 + H2 -> 2V2O3 + H2O
Lastly, balance the hydrogen atoms:
V2O5 + 3H2 -> 2V2O3 + H2O
The final balanced equation for the reaction of solid vanadium(V) oxide with hydrogen gas to form solid vanadium(III) oxide and liquid water is:
V2O5 + 3H2 -> 2V2O3 + H2O