The concentration of a certain sodium hydroxide solution was determined by using the solution to titrate a sample of potassium hydrogen phthalate (abbreviated KHP). KHP is an acid with one acidic hydrogen and a molar mass of 204.22 g/mol. In the titration 34.67 mL of the sodium hydroxide solution was reuired to react with 0.1082. g KHP. Calculate the molarity of the sodium hydroxide.

NaOH + KHP ==> NaKP + H2O

Note that 1 mol NaOH = 1 mol KPH.

mols KHP = grams/molar mass
mols NaOH = mols KHP.
M NaOH = mols NaOH/L NaOH. You now mols and L, solve for M

Oh, the mysterious world of titrations and molarity! Let's dive in, shall we?

To calculate the molarity of the sodium hydroxide solution, we need to use the equation:

Molarity (M) = moles solute / volume of solution (in liters)

First, we need to find the number of moles of KHP used. We can do this by dividing the given mass of KHP (0.1082 g) by its molar mass (204.22 g/mol):

moles KHP = 0.1082 g / 204.22 g/mol

Now, let's find the volume of the sodium hydroxide solution in liters. We know that 34.67 mL of the solution was used in the titration. To convert from milliliters to liters, we divide by 1000:

volume NaOH = 34.67 mL / 1000 mL/L

Finally, we can plug these values into the molarity equation:

Molarity NaOH = moles KHP / volume NaOH

And voila! You'll have your molarity of the sodium hydroxide solution. Keep in mind that the answer will depend on the specific values you plugged in, so go grab your calculator and crunch those numbers!

To calculate the molarity of the sodium hydroxide (NaOH) solution, we can use the equation:

Molarity (M) = (moles of solute) / (volume of solution in liters)

Step 1: Calculate the moles of KHP:

Mass of KHP = 0.1082 g
Molar mass of KHP = 204.22 g/mol

Moles of KHP = (mass of KHP) / (molar mass of KHP)
= 0.1082 g / 204.22 g/mol

Step 2: Convert the volume of the sodium hydroxide solution to liters:

Volume of NaOH solution = 34.67 mL = 0.03467 L

Step 3: Use the balanced chemical equation to determine the moles of NaOH:

The balanced chemical equation is:

KHP + NaOH → NaKP + H₂O

From the equation, we can see that the ratio between KHP and NaOH is 1:1.

So, the moles of NaOH = moles of KHP

Step 4: Calculate the molarity of NaOH:

Molarity (M) = (moles of NaOH) / (volume of NaOH solution in liters)
= (moles of KHP) / (volume of NaOH solution in liters)
= (0.1082 g / 204.22 g/mol) / 0.03467 L

Simplify the expression by dividing the numerator by the denominator:

Molarity of NaOH = (0.1082 / 204.22) / 0.03467

Using a calculator, we can calculate the molarity of the sodium hydroxide solution.

Molarity of NaOH ≈ 0.153 M (rounded to three significant figures)

Therefore, the molarity of the sodium hydroxide solution is approximately 0.153 M.

Thank you Dr. Bob

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