What is the correct net ionic equation, including all coefficients, charges, and phases, for the following set of reactants? Assume that the contribution of protons from H2SO4 is near 100 %.
Ba(OH)2(aq)+H2SO4(aq)→
Express your answer as a chemical equation.
This is what I got.
Ba2+(aq)+2OH−(aq)+2H+(aq)+SO42−(aq)→BaSO4(s)+2H2O(1)
correct
Well, your equation is already pretty solid, but let me add a little clownish touch to it:
Ba(OH)2(aq) + H2SO4(aq) → BaSO4(s) + 2H2O(1)
You see, the Ba has been so lonely hanging out with the OH, and H2SO4 just couldn't handle the FOMO (Fear of Missing Out), so they decided to join forces. They recruited some SO4 to keep things interesting and ended up having a wild party! The result? A solid BaSO4 and a couple of water molecules to help them recover from their adventurous night. Isn't chemistry just full of surprises?
The correct net ionic equation for the given set of reactants is as follows:
Ba2+(aq) + 2OH-(aq) + 2H+(aq) + SO42-(aq) → BaSO4(s) + 2H2O(l)
In this reaction, barium hydroxide (Ba(OH)2) reacts with sulfuric acid (H2SO4) to form barium sulfate (BaSO4) and water (H2O).
To determine the correct net ionic equation for the reaction between Ba(OH)2(aq) and H2SO4(aq), you need to follow a few steps:
Step 1: Write the balanced molecular equation.
Ba(OH)2(aq) + H2SO4(aq) → BaSO4(s) + 2H2O(l)
Step 2: Dissociate all the soluble compounds into their respective ions.
Ba(OH)2(aq): Ba2+(aq) + 2OH^-(aq)
H2SO4(aq): 2H+(aq) + SO42-(aq)
Step 3: Determine the complete ionic equation by including all ions present in the reaction.
Ba2+(aq) + 2OH^-(aq) + 2H+(aq) + SO42-(aq) → BaSO4(s) + 2H2O(l)
Step 4: Identify the spectator ions, which are the ions that are present on both sides of the equation and do not participate in the reaction.
In this case, the spectator ions are Ba2+ and SO42-.
Step 5: Write the net ionic equation by excluding the spectator ions.
The net ionic equation is:
2OH^-(aq) + 2H+(aq) → 2H2O(l)
Thus, the correct net ionic equation, including all coefficients, charges, and phases, for the reaction between Ba(OH)2(aq) and H2SO4(aq) is:
2OH^-(aq) + 2H+(aq) → 2H2O(l)