A card is chosen at random from a deck of 52 cards It is then replaced and then a second card is chosen.What is the probability of choosing a jack and then an eight?

as long as it is replaced, the events are independent

4/52 * 4/52

answer is 1/169

To calculate the probability of choosing a jack and then an eight, we need to determine the probability of each event happening and then multiply them together.

Step 1: Determine the probability of choosing a jack.
There are four jacks in a standard deck, so the probability of selecting a jack on the first draw is 4/52. Since the card is replaced, the deck remains the same for the second draw.

Step 2: Determine the probability of choosing an eight.
Just like the jacks, there are four eights in a deck. So, the probability of selecting an eight on the second draw is also 4/52.

Step 3: Multiply the probabilities.
To calculate the probability of both events occurring, we multiply the probabilities together:
(4/52) * (4/52) = 16/2704 ≈ 0.00592

Therefore, the probability of choosing a jack and then an eight from a deck of 52 cards, with replacement, is approximately 0.00592, or about 0.59%.

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a card is chosen at random from a deck of cards, replace, then another card is chosen. what is the probility of choosing a dimande both times. answer

By the way, they were trying to trick you.

If the Jack were NOT replaced, there would only be 51 cards when you went to pick the 8.
Then it WOULD HAVE BEEN 4/52 * 4/51