To find the product 3/7 multiplied by 4/9, Cameron simplified 3/7 to 1/7 and then multiplied the fractions 1/7 and 4/9 to find the product 4/63. What is Cameron's error? Please help answer thanks
he should not have simplified the 3/7
Cameron's error lies in simplifying the fraction 3/7 to 1/7. To find the product of fractions, you cannot simplify the numbers individually before multiplying. Instead, you need to multiply the numerators and the denominators directly.
To correctly find the product of 3/7 and 4/9, you can multiply the numerators (3 * 4) to get 12 and multiply the denominators (7 * 9) to get 63.
Therefore, the actual product of 3/7 and 4/9 is 12/63, not 4/63.
Cameron's error lies in simplifying the fraction 3/7 to 1/7. To understand the mistake, let's break down the process and find the correct solution.
To find the product of 3/7 multiplied by 4/9, we first need to multiply the numerators (the numbers on top) and then multiply the denominators (the numbers on the bottom). So, the correct calculation is:
(3/7) * (4/9) = (3 * 4) / (7 * 9) = 12/63
Therefore, the simplified product is 12/63.
Cameron's error was in incorrectly simplifying 3/7 to 1/7. Here is how you can simplify the fraction properly:
To simplify a fraction, we need to divide both the numerator and denominator by their greatest common divisor (GCD). In this case, the GCD of 3 and 7 is 1 since they do not have any common factors other than 1.
So, dividing both the numerator and the denominator of 3/7 by 1, we get:
(3/1) / (7/1) = 3/7
Therefore, the correct representation of 3/7 is still 3/7, and there is no need to simplify it further.
In conclusion, Cameron's error was mistakenly simplifying 3/7 to 1/7, resulting in an incorrect product of 4/63. The correct answer is 12/63.