Which reaction of ammonia does not involve the non-bonding pair of electrons on the nitrogen atom?

A NH3(g) + CH3I(g) → CH3NH 3+ I –(s)
B NH3(g) + HCl (g) → NH4Cl (s)
C 2NH3(l) + 2Na(s) → 2NaNH2(s) + H2(g)
D 2NH3(aq) + Ag+(aq) → [Ag(NH3)2]+(aq)

Answer: C
And explanation please! Thanks!

:NH3 + Na.

Here is the best I can do for Lewis structure of NH3.
H
..
:N:H + Na.
..
H
Let's pick on the right most H. It leaves and takes its electron with it as H.
The Na. donates its electron to make ionic bond and one molecule of NaNH2 with Na^+ charge and NH2^- with H. left over. Take another Na. and another NH3 and do the same thing. That gives you two molecules of NaNH2 (ionic compound) and two H. atoms and they combine to form H:H We never touched the non-bonding pair.
In A answer the H^+ sits down on the non-bonding pair to make the + ion (it's now bonding isn't it).
In B the H from HCl does the same think to form the NH4^+.
In C the explanation is above and the non-bonding is not used.
In D the non-bonding pair of those NH3 molecules goes to fill up the unused orbitals in Ag^+. Remember that a Lewis base is one that donates electrons; the NH3 donates electrons to the Ag^+

C: 2NH3(l) + 2Na(s) → 2NaNH2(s) + H2(g)

Explanation: In this reaction, the nitrogen atom in ammonia (NH3) donates a lone pair of electrons to sodium (Na) to form NaNH2. The non-bonding pair of electrons on the nitrogen atom is involved in the formation of a new bond with the sodium atom.

In reactions A, B, and D, the non-bonding pair of electrons on the nitrogen atom is not involved. In reaction A, the lone pair on nitrogen is not involved because it is the methyl group that is undergoing a reaction with CH3I. In reaction B, the lone pair on nitrogen is not involved because it is the hydrochloric acid (HCl) molecule that is reacting with NH3. In reaction D, the lone pair on nitrogen is not involved because it is the silver ion (Ag+) that is reacting with NH3.

Therefore, the correct answer is C (2NH3(l) + 2Na(s) → 2NaNH2(s) + H2(g)) because it is the only reaction where the non-bonding pair of electrons on the nitrogen atom is not involved in the reaction.

The reaction that does not involve the non-bonding pair of electrons on the nitrogen atom is option C, which is:

C) 2NH3(l) + 2Na(s) → 2NaNH2(s) + H2(g)

In this reaction, ammonia (NH3) reacts with sodium (Na) to form sodium amide (NaNH2) and hydrogen gas (H2). This reaction does not involve the non-bonding pair of electrons on the nitrogen atom. The reaction occurs through the breaking and formation of covalent bonds between the atoms.

The other options involve the non-bonding pair of electrons on the nitrogen atom:

Option A:
NH3(g) + CH3I(g) → CH3NH 3+ I –(s)

In this reaction, the non-bonding pair of electrons on the nitrogen atom of ammonia attacks the carbon atom of methyl iodide, leading to the formation of a new bond and the formation of CH3NH3+ and I- ions.

Option B:
NH3(g) + HCl (g) → NH4Cl (s)

In this reaction, the non-bonding pair of electrons on the nitrogen atom of ammonia attacks the hydrogen atom in hydrogen chloride, leading to the formation of a new bond and the formation of NH4+ and Cl- ions.

Option D:
2NH3(aq) + Ag+(aq) → [Ag(NH3)2]+(aq)

In this reaction, the non-bonding pair of electrons on the nitrogen atom of ammonia interacts with the silver ion (Ag+), leading to the formation of a coordinate bond and the formation of [Ag(NH3)2]+ ion.

Therefore, option C is the correct answer as it is the only reaction that does not involve the non-bonding pair of electrons on the nitrogen atom.

To determine which reaction of ammonia does not involve the non-bonding pair of electrons on the nitrogen atom, we need to examine the reactions and identify whether the nitrogen atom donates its non-bonding pair of electrons or not.

A NH3(g) + CH3I(g) → CH3NH3+ I–(s):
In this reaction, the nitrogen atom in NH3 donates its non-bonding electron pair to form a coordinate covalent bond with the CH3 group, resulting in the formation of CH3NH3+. Hence, this reaction involves the non-bonding pair of electrons on the nitrogen atom.

B NH3(g) + HCl(g) → NH4Cl(s):
In this reaction, the nitrogen atom donates its non-bonding electron pair to the hydrogen atom of HCl to form NH4+ (ammonium ion). This reaction also involves the non-bonding pair of electrons on the nitrogen atom.

C 2NH3(l) + 2Na(s) → 2NaNH2(s) + H2(g):
In this reaction, there is no mention of the non-bonding electron pair on the nitrogen atom. Instead, the reaction involves the formation of sodium amide (NaNH2) and hydrogen gas (H2). The non-bonding pair of electrons on the nitrogen atom does not participate, making this the correct answer.

D 2NH3(aq) + Ag+(aq) → [Ag(NH3)2]+(aq):
In this reaction, the nitrogen atom donates its non-bonding electron pair to the Ag+ ion, forming a complex ion [Ag(NH3)2]+. Therefore, this reaction also involves the non-bonding pair of electrons on the nitrogen atom.

Therefore, the reaction that does not involve the non-bonding pair of electrons on the nitrogen atom is option C: 2NH3(l) + 2Na(s) → 2NaNH2(s) + H2(g).

Well, it's still too confusing. Make it simple.

Thankyou smart human.