If the acceleration due to gravity on the Moon is 1/6 that what is on the Earth, what would a 100 kg man weight on the Moon? If a person tried to simulate this gravity in an elevator, how fast would it have to accelerate and in which direction?
a. m*g/6 = 100kg * (9.8/6)N/kg = 163.3 N. = Wt. on the moon.
Any body which has mass x on the earth will be x/6 on moon.so the man will be 100/6kg=16.3kg.
can you explain to me better, please?
thank you so much
To find out the weight of a person on the Moon, we can use the formula:
Weight = mass x acceleration due to gravity
On Earth, the acceleration due to gravity is approximately 9.8 m/s², and on the Moon, it is 1/6th of Earth's gravity. So, on the Moon, the acceleration due to gravity is:
Acceleration on Moon = 1/6 * 9.8 m/s² = 1.63 m/s²
Now, we need to calculate the weight of a 100 kg man on the Moon:
Weight on Moon = mass x acceleration on Moon
= 100 kg x 1.63 m/s²
= 163 kg·m/s²
= 163 N
Therefore, a 100 kg man would weigh 163 Newtons on the Moon.
Now, let's address the second part of your question regarding simulating the Moon's gravity in an elevator.
In a scenario where an elevator is used to simulate Moon's gravity, the elevator would need to accelerate downwards at the same rate as the Moon's gravity, which is 1.63 m/s². This means the elevator would have to accelerate downwards with an acceleration of 1.63 m/s².
The direction of the acceleration would be downward since to simulate gravity, the elevator needs to create a force opposite to the natural direction of gravity. Hence, the elevator would need to accelerate downwards at 1.63 m/s² to give the effect of Moon's gravity.