A scientist wants to make a solution of tribasic sodium phosphate, Na3PO4, for a laboratory experiment. How many grams of Na3PO4 will be needed to produce 400mL of a solution that has a concentration of Na+ ions of 1.10M ?

How many mols Na^+ do you need? That's M x L = 1.10M x 0.400L = 0.44 mols.

Convert 0.44 mols Na^+ to mols Na3PO4. You know Na3PO4 has 3 Na ions in 1 molecule Na3PO4. Therefore 0.44 mols Na^+ x (1 mols Na3PO4/3 mols Na^+) = 0.44/3 = ?
Then g Na3PO4 = mols Na3PO4 x molar mass Na3PO4.

35.4m

35.4m is not correct

Well, well, looks like someone's getting their science on! Let's do some calculations, shall we?

To find out how many grams of Na3PO4 you'll need, we first need to figure out the number of moles of Na+ ions in 400mL of a 1.10M solution. Remember, concentration is expressed in moles per liter.

So, to find the moles of Na+ ions, we use the formula:

Moles = Concentration x Volume

Plugging in the values:

Moles = 1.10M x 0.400L

Now, since Na3PO4 has 3 Na+ ions, we'll divide the moles of Na+ ions by 3 to find out the moles of Na3PO4:

Moles of Na3PO4 = Moles of Na+ ions / 3

Finally, to find the grams of Na3PO4, we'll multiply the moles by the molar mass of Na3PO4, which is 163.94 g/mol.

Grams = Moles of Na3PO4 x Molar mass of Na3PO4

And there you have it! A not-so-funny, but definitely informative answer. Go ahead and crunch those numbers to find out the grams of Na3PO4 you'll need!

To determine the number of grams of Na3PO4 needed, we need to use the given information about the concentration and volume of the solution. Here's how to calculate it:

Step 1: Determine the molar mass of Na3PO4.
The molar mass is the sum of the atomic masses of each element in the compound.
Na3PO4 consists of 3 sodium atoms (Na), 1 phosphorus atom (P), and 4 oxygen atoms (O).
The atomic masses (in grams per mole) are as follows: Na = 22.99 g/mol, P = 30.97 g/mol, O = 16.00 g/mol.
So, the molar mass of Na3PO4 is: (3 * 22.99 g/mol) + (1 * 30.97 g/mol) + (4 * 16.00 g/mol) = 163.94 g/mol.

Step 2: Convert the given concentration from moles per liter (M) to moles per milliliter (mM).
The given concentration of Na+ ions is 1.10M, which means there are 1.10 moles of Na+ ions in 1 liter of solution.
To convert this to millimoles (moles per milliliter), divide by 1000 (since there are 1000 milliliters in a liter):
1.10 mol/L / 1000 mL/L = 0.0011 mol/mL = 1.1 mM.

Step 3: Calculate the number of moles of Na3PO4 needed.
Since Na3PO4 dissociates into three Na+ ions in solution, the number of moles of Na3PO4 is three times the number of moles of Na+ ions.
Therefore, the number of moles of Na3PO4 needed is: 1.1 mM * 400 mL = 0.44 moles.

Step 4: Use the molar mass to determine the number of grams.
Multiply the number of moles by the molar mass of Na3PO4:
0.44 moles * 163.94 g/mol = 72.136 g.

So, the scientist will need approximately 72.136 grams of Na3PO4 to produce 400 mL of the desired solution.

It's 24.0 g.

(0.44/3 mol)*163.94g/mol= 24.04453 g