Create an image of a large luxurious vehicle, possibly a sedan or a limousine, painted in a rich black color. Make it appear to be in motion, with blurred surroundings suggesting high speed. The background should be an open road barren landscape on a bright sunny day. As the car comes to a halt, illustrate the dramatic effect of the quick stop by highlighting brake lines along the road. Ensure the entire scene is without text.

A big luxury car weighing 1.96 x 104 N (about 4400 lb), travelling in the x

direction makes a fast stop; the x component of the net force acting on it is -1.50x 104
N. What is its acceleration?

F = ma

-1.50*10^4 = (1.96*10^4/9.81)(a)

Well, that luxury car really knows how to make an entrance! It's like it slammed on the brakes and said, "Whoa there, let's take it slow!" Now, let's get down to business.

The net force acting on the car is -1.5 x 10^4 N, which is pointing in the opposite direction of its motion. We know that force equals mass times acceleration (F = ma), so we just need to rearrange the equation to solve for acceleration.

Rearranging the equation, we have a = F/m. Plugging in the values, we get:

a = (-1.5 x 10^4 N) / (1.96 x 10^4 N)

Doing the math, the acceleration of the car is approximately -0.765 m/s^2.

So, to sum it up, that luxury car went from zooming to a screeching halt with an acceleration of -0.765 m/s^2. Looks like it's time for the passengers to hold onto their hats!

To find the acceleration of the car, we can use Newton's second law of motion, which states that the net force acting on an object is equal to its mass multiplied by its acceleration:

F_net = m * a

In this case, the net force acting on the car is -1.50x 10^4 N, and the weight of the car is 1.96 x 10^4 N. Since weight is the force acting due to gravity, we can assume that the net force and weight are acting in opposite directions:

F_net = -F_weight

Substituting the values:

-1.50 x 10^4 N = -1.96 x 10^4 N * a

Now, we can solve for the acceleration (a):

a = (-1.50 x 10^4 N) / (-1.96 x 10^4 N)

a ≈ 0.765

Therefore, the acceleration of the car is approximately 0.765 m/s².

To find the acceleration of the car, you need to use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration:

Fnet = m * a

In this case, the net force acting on the car in the x-direction is -1.50 x 10^4 N. The weight of the car can be considered as the force acting on it due to gravity, so the weight of the car is 1.96 x 10^4 N.

Since weight is equal to mass multiplied by gravitational acceleration (W = m * g), we can rearrange the equation to find the mass of the car (m):

m = W / g

Where g is the acceleration due to gravity, which is approximately 9.8 m/s^2.

Substituting the values, we get:

m = 1.96 x 10^4 N / 9.8 m/s^2 ≈ 2000 kg

Now we have the mass of the car, we can use the formula Fnet = m * a to solve for acceleration (a):

-1.50 x 10^4 N = 2000 kg * a

Dividing both sides of the equation by 2000 kg, we find:

a = (-1.50 x 10^4 N) / (2000 kg) ≈ -7.5 m/s^2

So, the acceleration of the car is approximately -7.5 m/s^2.