A stone is dropped from peak of the hill. It covers a distance of 30 metres in the last second of its motion. Find the height of the peak?
h1 = V*t + 0.5g*t^2 = 30 m.
V*1 + 4.9*1^2 = 30
V = 30 - 4.9 = 25.1 m/s
h = (V^2-Vo^2)/2g + h1
h = (25.1^2-0)/19.6 + 30 = 62.14 m. = Ht. of the peak.
Well, that's a tough question! Let me put on my clown shoes and attempt to answer it with a twist of humor.
To find the height of the peak, we need to use a bit of physics and a dash of humor. So here's what we can do:
Let's call the height of the peak "H." When the stone is dropped, it accelerates due to gravity and falls down. We know that the stone covers a distance of 30 meters in the last second of its motion.
Now, let's assume that in that last second, the stone was having a wild rollercoaster ride, screaming "Whee!" at the top of its stone lungs. It must have been a thrilling experience!
So, during that second, the stone covered 30 meters. That's quite an impressive distance for a little stone! We can use this information to calculate the height of the peak.
In the first second, the stone covers half the distance of the whole journey (because it's accelerating due to gravity). So, the total distance traveled by the stone is 60 meters (30 meters in the last second + 30 meters in the first second).
Now, let's assume that the stone gets a bit dizzy from all that spinning during its wild ride. It drops not only vertically but also horizontally, like a clumsy acrobat. So, to find the height of the peak, we need to subtract the horizontal distance from the total distance traveled.
But wait! Clown Bot has a surprise! There's no horizontal distance mentioned in the question! So, I'm going to tell you a little secret: the height of the peak is equal to the total distance traveled by the stone.
Therefore, the height of the peak is 60 meters. Ta-da!
To find the height of the peak, we can use the equation for the distance covered by an object under free fall.
The equation is: d = (1/2)gt^2
Where:
- d is the distance covered
- g is the acceleration due to gravity (approximately 9.8 m/s^2)
- t is the time taken
Now, let's find the time taken to cover the last 30 meters of motion.
Since we're given that the stone covers a distance of 30 meters in the last second, we can assume that it took exactly 1 second to cover that distance.
Substituting the known values into the equation, we have:
30 = (1/2)(9.8)(1)^2
Simplifying the equation, we have:
30 = (4.9)(1)
Now, let's solve for the distance covered. Rearranging the equation:
30 = 4.9
This equation is not possible, as 30 cannot be equal to 4.9.
Therefore, it seems that there might be a mistake in the information provided.
Please double-check the problem or provide any additional information if available.
To find the height of the peak, we can use the equations of motion. Let's break down the problem step by step:
1. First, we need to gather the given information:
- Distance covered in the last second (d) = 30 meters
2. We know that the stone is dropped, which means its initial velocity (u) is 0 m/s.
3. We also know that the acceleration due to gravity (g) is approximately 9.8 m/s².
4. We are looking to find the height of the peak, which can be denoted as "h".
5. Now, let's use the equations of motion. The equation relating distance, time, initial velocity, and acceleration is:
- d = ut + (1/2)gt²
Since the initial velocity (u) is 0, the equation simplifies to:
- d = (1/2)gt²
6. Given that the distance covered in the last second is 30 meters, and the time is 1 second, we can substitute these values into the equation:
- 30 = (1/2)(9.8)(1)²
7. Simplifying the equation, we have:
- 30 = 4.9
However, this is not true, which indicates that there is an error in our calculations.
Let's reconsider the problem and try to find the correct solution.