A car begins at rest at t0 = 0. The car starts moving and finally covers a distance d = 617 m in a time tf = 105 s. In a coordinate system with north being the positive x-direction, the car's motion is in the southern direction. What was the car's average speed during this period, in meters per second?.
To find the average speed of the car, we can use the formula:
Average speed = Total distance / Total time
Given:
Total distance (d) = 617 m
Total time (tf) = 105 s
Using the formula, we can calculate the average speed:
Average speed = 617 m / 105 s
Average speed ≈ 5.876 m/s
Therefore, the car's average speed during this period is approximately 5.876 meters per second.
To find the car's average speed during this period, we need to divide the total distance covered by the time taken.
Average Speed = Total Distance / Time
In this case, the total distance covered by the car is given as d = 617 m, and the time taken is given as tf = 105 s.
Therefore, we can calculate:
Average Speed = 617 m / 105 s
To get the average speed, we divide the distance (617 m) by the time (105 s), which gives us:
Average Speed = 5.876 m/s (rounded to three decimal places)
So, the car's average speed during this period is approximately 5.876 meters per second.
average velocity = -617/105
= -5.88 m/s
and
average speed = 5.88 m/s
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in anticipation of a part B:
x = Xi + Vi t + (1/2) a t^2
-617 = 0 + 0 t + (1/2)a (105)^2
a = -1234/105^2
a = - .112 m/s^2