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A 25 kg box is along a horizontal floor and a force of 400 N pushes the box with an angle of 50 deg with the horizontal. Starting from rest, the box achieves a velocity of 2 m/s in a time of 4 seconds. Find the coefficient of sliding friction between box and the floor.

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4 answers
  1. break the pushing force into vertical and horizonal components, Fv, Fh

    Fv=400sin50
    Fh=400cos50

    Now, write the force equation
    forcetotal=ma
    fh-mu*(mg+Fv)=ma solve for mu, knowing acceleration is frdom
    a=changevelocity/time=2/4 m/s^2=.5m/s^2

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    bobpursley
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  3. What would be the weight of the box?

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