If an ion contains 50 protons,68 neutrons and 48 electrons.what is its symbol?
Sn+2
50 protons
To determine the symbol of an ion, we need to know the number of protons and the charge of the ion. The charge of an ion is determined by the difference between the number of protons (positive charge) and the number of electrons (negative charge).
Here's how we can determine the charge of the ion and its symbol:
1. First, determine the number of protons from the given information. In this case, the ion contains 50 protons.
2. Next, determine the number of electrons. The number of electrons is given as 48.
3. Calculate the charge of the ion by subtracting the number of electrons from the number of protons:
Charge = Number of protons - Number of electrons
= 50 - 48
= +2
Since the charge is positive (+2), the ion is a cation.
4. Finally, write the symbol of the ion by using the element's symbol and indicating the charge as a superscript.
The element with 50 protons is tin (Sn). So, the symbol of the ion with 50 protons, 68 neutrons, and 48 electrons and a +2 charge is:
Sn²⁺