The figure shows 2 similar squares, A and B which overlap each other. The ratio of the shaded area to the total area of square B is 3:5. The ratio of the shaded area to the total area of square A is 9:17. What is the ratio of the shaded area to the total unshaded areas of the figure?
we have
s/b = 3/5
s/a = 9/17
total unshaded area is a+b-s, and we want
s/(a+b-s)
we know that
b = 5/3 s
a = 17/9 s
so, we have
s/(a+b-s) = s/(5/3 s + 17/9 s - s)
= s/(23/9 s)
= 9/23
9/23
It is supposed to be 9/14.
no
To find the ratio of the shaded area to the total unshaded areas of the figure, we first need to determine the ratios of the shaded area to the total area for both squares A and B.
Let's assume that the area of square A is A, and the area of square B is B.
The first given ratio tells us that the shaded area of square B is 3/5 of the total area of square B. Therefore, the shaded area of square B is (3/5) * B.
Likewise, the second given ratio tells us that the shaded area of square A is 9/17 of the total area of square A. Therefore, the shaded area of square A is (9/17) * A.
Now, let's calculate the unshaded areas of both squares.
The unshaded area of square B is given by the difference between the total area of square B and its shaded area. Therefore, the unshaded area of square B is B - (3/5) * B, which simplifies to (2/5) * B.
Similarly, the unshaded area of square A is given by the difference between the total area of square A and its shaded area. Therefore, the unshaded area of square A is A - (9/17) * A, which simplifies to (8/17) * A.
To find the ratio of the shaded area to the total unshaded areas of the figure, we need to sum up the shaded areas of both squares and divide it by the sum of the unshaded areas of both squares:
((3/5) * B + (9/17) * A) / ((2/5) * B + (8/17) * A)
Now, we can simplify this expression by finding a common denominator:
(17 * (3B) + 5 * (9A)) / (17 * (2B) + 5 * (8A))
(51B + 45A) / (34B + 40A)
Therefore, the ratio of the shaded area to the total unshaded areas of the figure is (51B + 45A) : (34B + 40A).