C2H4(g) + H2(g) → C2H6(g)
given that the enthalpy of combustion for the reactants and products are:
ΔHºc(C2H4)(g) = -1411 kJ mol^-1
ΔHºc(C2H6)(g) = -1560 kJ mol^-1
ΔHºc(H2)(g) = -286 kJ mol^-1
See your post above.
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