Given that 2 log base2 (x+15)  log base2 x = 6
1.Show that x^2 34x +225 = 0
2. Hence or otherwise solve the equation 2 log base 2 (x+15)  log base 2 x =6
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1 answer

2 log base2 (x+15)  log base2 x = 6
log(x+15)^2  logx = 6
(x+15)^2/x = 2^6
(x+15)^2 = 64x
x^2+30x+225 = 64x
x^234x+225 = 0 👍
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answered by Steve
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