How many gram ofsodiun fluoride should be added to 100000liter of drinking water containing 0.6 ppm of sodium fluoride to provide a recommended concentration of 1.75 ppm
1.75-0.6ppm=1.15ppm
Which means 1.15g in 10^6mls
So how many grams in 10litres.
Change litres into mls and calculate
Answer will be 115g
Thank you .. but the right answer in my book is 115g
look at the amounts of NaF involved:
(.6/10^6)*100000 + 1.0*x = (1.75/10^6)(100000+x)
x = 0.115
check:
.6 ppm in 10^5L = 0.06g
add 0.115 g and you have 0.175g, or 1.75ppm
Hmm. Obviously I misplaced a decimal point. I expect you can find the flaw in my reasoning.
Ah, fluoride, a mineral that helps keep those pearly whites happy and healthy! Let's do some fun calculations to figure out how much sodium fluoride you'll need.
First, let's convert the given concentration of 0.6 ppm into a more manageable unit. 1 ppm is equivalent to 1 mg per liter, so 0.6 ppm is equal to 0.6 mg per liter.
Now, to find out how many milligrams of sodium fluoride are present in the 100,000 liters of drinking water, we multiply 0.6 mg/L by 100,000 L:
0.6 mg/L * 100,000 L = 60,000 mg
Since we want to achieve a concentration of 1.75 ppm, we'll need to subtract the initial concentration of sodium fluoride we already have (0.6 ppm or 0.6 mg/L) from the target concentration (1.75 ppm or 1.75 mg/L):
1.75 mg/L - 0.6 mg/L = 1.15 mg/L
Now, multiply the difference in concentration (1.15 mg/L) by the volume of water (100,000 L) to find out how many milligrams of sodium fluoride you need to add:
1.15 mg/L * 100,000 L = 115,000 mg
But wait! We need the amount in grams, not milligrams, so let's convert it. There are 1,000 milligrams in 1 gram:
115,000 mg / 1,000 = 115 grams
So, my friend, you'll need to add 115 grams of sodium fluoride to reach the recommended concentration of 1.75 ppm in your 100,000 liters of drinking water. Just be sure to handle it with care and keep those jokes flowing while you're at it!
To calculate the grams of sodium fluoride required, we need to consider the volume and concentration of the solution. Here's how you can do it:
Step 1: Convert the volume of the water from liters to milliliters.
1 liter = 1000 milliliters
Therefore, 100000 liters = 100000000 milliliters
Step 2: Calculate the initial amount of sodium fluoride in the 100000 liters of water.
Initial concentration = 0.6 ppm = 0.6 mg/L = 0.6 μg/mL
Initial amount of sodium fluoride = Initial concentration * Volume
= 0.6 μg/mL * 100000000 mL
= 60000000 μg
Step 3: Calculate the final amount of sodium fluoride required.
Final concentration = 1.75 ppm = 1.75 mg/L = 1.75 μg/mL
Final amount of sodium fluoride = Final concentration * Volume
= 1.75 μg/mL * 100000000 mL
= 175000000 μg
Step 4: Calculate the difference in the amounts.
Difference in amount = Final amount - Initial amount
= 175000000 μg - 60000000 μg
= 115000000 μg
Step 5: Convert the difference in amount from micrograms to grams.
1 μg = 1e-6 g
Therefore, 115000000 μg = 115 grams
Therefore, you will need to add 115 grams of sodium fluoride to the 100000 liters of drinking water to achieve the recommended concentration of 1.75 ppm.