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In the following reaction, 28 grams of Calcium Oxide CaO reacts with Carbon Dioxide CO2 to produce Calcium Carbonate CaCO3. How much Calcium Carbonate is produced?

CaO+CO2 ---> CaCO3

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  1. CaO + CO2 --> CaCO3

    atomic masses
    Ca = 40
    O = 16
    C = 12
    so
    CaO is 40 + 16 = 56 grams/mol
    28/56 = .5 mol

    so we get .5 mol of CaCO3
    CaCO3 = 40 + 12 + 48 = 100 grams/mol

    so we get 50 grams of CaCO3

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