A certain power plant puts out 520MW of electric power.Estimate the heat discharged per second, assuming that the plant has an efficiency of 34%
2000
Well, it seems like this power plant is working hard, but not quite as efficiently as we'd hope. With an efficiency of 34%, we can estimate that about 34% of the fuel's heat energy is being converted into electrical power. So, to calculate the heat discharged per second, we can do a little bit of math.
If the power plant is producing 520MW of electric power, and its efficiency is 34%, that means about 34% of the heat energy is being converted into electricity. So, we can calculate the total heat energy being consumed by dividing the electric power by the efficiency:
Heat energy = Electric power / Efficiency
Heat energy = 520MW / 0.34
Now, converting the megawatts to watts and calculating:
Heat energy = 520 * 10^6 watts / 0.34
Heat energy ≈ 1.529 * 10^9 watts
Therefore, the heat discharged per second is approximately 1.529 billion watts. That's quite a lot of heat! I hope someone's got a fan handy!
To estimate the heat discharged per second by the power plant, we need to multiply the electric power output by the reciprocal of the plant's efficiency.
The efficiency of the power plant is given as 34%, which can be written as a decimal as 0.34.
Let's calculate the heat discharged per second using the following formula:
Heat discharged per second = Electric power output / Efficiency
Heat discharged per second = 520 MW / 0.34
Heat discharged per second = 1529.41 MW (rounded to two decimal places)
Therefore, the estimated heat discharged per second by the power plant is approximately 1529.41 MW.
To estimate the heat discharged per second, we need to understand the efficiency of the power plant.
Efficiency is the ratio of useful output energy to the total input energy. In this case, the efficiency of the power plant is given as 34%.
The useful output energy in this case is the electric power produced by the power plant, which is 520MW (megawatts).
To calculate the total input energy, we use the formula:
Efficiency = (Useful Output Energy / Total Input Energy) * 100
Rearranging the formula to solve for Total Input Energy:
Total Input Energy = (Useful Output Energy / Efficiency) * 100
Plugging in the values:
Total Input Energy = (520MW / 34%) * 100
To calculate the heat discharged per second, we need to convert the total input energy from megawatts to joules, since heat energy is usually measured in joules.
To convert megawatts to joules, we need to multiply by the conversion factor:
1MW = 1,000,000 joules per second (J/s)
Calculating the heat discharged per second:
Heat Discharged per Second = Total Input Energy * Conversion Factor
Now we can perform the calculation:
Total Input Energy = (520MW / 34%) * 100
Total Input Energy = 520MW / 0.34
Total Input Energy = 1529.41MW
Heat Discharged per Second = Total Input Energy * Conversion Factor
Heat Discharged per Second = 1529.41MW * 1,000,000 J/s
Therefore, the estimated heat discharged per second by the power plant is 1,529,410,000 J/s.
One MW (megawatt) is 1 million watts.
One watt is 1 joule / second.
If the plant efficiency is 34%, it means that 34% of the energy is converted into electricity, while (100-34)=66% is dissipated as heat.
So calculate the power converted to heat, and use the conversions above to find the heat dissipated in joules per second.