A simple lever is used to lift a heavy load. When a 60-N force pushes one end of the lever down 1.2 m, the load rises 0.2 m. Show that the weight of the load is 360 N.
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Work done by force = work done by load (W)
60 N * 1.2 m = 0.2 m * W
Solve for W to get
W=60*1.2/0.2 N
= 360 N
60N x 1.2m =0.2 x the weight of the load.
As 60 x 1.2/0.2=360N
shown
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60N *1.2M=0.2-0*M
To determine the weight of the load, we need to use the principle of moments, which states that the total sum of clockwise moments about a pivot point is equal to the total sum of anticlockwise moments about the same pivot point. In this case, the pivot point is the fulcrum of the lever.
Let's assign variables to the given information:
- Force applied to one end of the lever (effort force): F = 60 N
- Distance from the effort force to the fulcrum: d1 = 1.2 m
- Distance from the load to the fulcrum: d2 = 0.2 m
- Weight of the load: W (what we are trying to find)
Now, we can express the principle of moments mathematically as:
F × d1 = W × d2
Substituting the known values:
60 N × 1.2 m = W × 0.2 m
Simplifying the equation:
72 Nm = 0.2 W
To solve for W, divide both sides of the equation by 0.2 m:
W = 72 Nm / 0.2 m
W = 360 N
Therefore, the weight of the load is 360 N.