A regular hexagon is drawn inside of a circle so that each of its vertices touches the circle. The diameter of the circle is 4 centimeters and the perimeter of the hexagon is 12 centimeters. How much longer is the circumference of the circle than the perimeter of the hexagon? (use 3.14 for pi)

The answer for your question is simple, π = 3.14, so, first you multiply 4 by 3.14, then it comes to 12.56, right? Yes. The last thing you need to do is to subtract 12 from 12.56 and you get 0.56! :) Hope this helps! ;)

the circumference is 4pi

the perimeter is 12

so, 4pi - 12 = ?

Find perimeter of a regular hexigon with 6 equal sides and with equal interior angles. That is inscribed in a circle, all vertices touch the circle ) of radius 10.0 meters.

To solve this problem, we need to find the circumference of the circle and the perimeter of the hexagon, and then calculate the difference between the two.

Let's start with the perimeter of the hexagon. Since the hexagon has 6 equal sides, each side would have a length of 12 cm / 6 = 2 cm. Therefore, the perimeter of the hexagon is 6 * 2 cm = 12 cm.

Next, let's find the circumference of the circle. We are given that the diameter is 4 cm, so the radius would be 4 cm / 2 = 2 cm. The circumference of a circle is given by the formula C = 2πr, where π is approximately 3.14. Therefore, the circumference of the circle is 2 * 3.14 * 2 cm = 12.56 cm.

Now, we can find the difference between the circumference of the circle and the perimeter of the hexagon. The difference would be 12.56 cm - 12 cm = 0.56 cm.

Therefore, the circumference of the circle is 0.56 cm longer than the perimeter of the hexagon.