Jabari is thinking of three numbers. The greatest number is twice as big as the least number. The middle number is three more than the least number. The sum of the three numbers is 75. Find the numbers.
In this case, use variables to represent the numbers. Fortunately, they are all in terms of the smaller number. So, let...
x = small number
(x + 3) = middle number
2x = large number
If the sum is 75, then all of the numbers added together must equal this. So...
x + (x+3) + 2x = 75
4x + 3 = 75
4x = 72
x = 18
After we find x, we can conclude that...
Smaller number = 18
Middle number = 21
Large number = 36
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But can you solve for X. that is the question on my paper what is x
Yes, I did this question on CPM, and my thought process was: Greater than 10, Less than 20, Greater than 15, So, then I got 18 for my final answer.
To find the three numbers, let's assign variables to them.
Let's call the least number "x."
Since the greatest number is twice as big as the least number, we can write it as "2x."
And the middle number is three more than the least number, so we can write it as "x + 3."
Now, according to the problem, the sum of the three numbers is 75. So we can create an equation:
x + (2x) + (x + 3) = 75
Simplifying the equation:
4x + 3 = 75
Next, let's isolate the variable:
4x = 75 - 3
4x = 72
Dividing both sides by 4:
x = 72 / 4
x = 18
Now that we know the value of x, we can find the other two numbers:
The greatest number: 2x = 2 * 18 = 36
The middle number: x + 3 = 18 + 3 = 21
So the three numbers are 18, 21, and 36.