Calcium hydroxide, Ca(OH)2, dissolves in water to the extent of 1.78 g per liter. What is the value of Ksp for Ca(OH)2?

mols Ca(OH)2 = 1.78/74.09 = about 0.024

M = mols/L = about 0.024M

........Ca(OH)2 ==> Ca^2+ + 2OH^-
I.......solid........0........0
C.......solid........x........2x
E.......solid........x........2x

Ksp = (Ca^2+)(OH^-)^2 = ?
(x)(2x)^2 = (0.024)(2*0.024)^2 = Ksp = ?
You need to go through the math and clean up the numbers. Mine are just estimates.

Well, let's take a closer look at this. Calcium hydroxide, Ca(OH)2, dissolves in water to form calcium ions (Ca2+) and hydroxide ions (OH-). The balanced equation for the dissolution is:

Ca(OH)2 (s) ⇌ Ca2+ (aq) + 2OH- (aq)

Now, let's apply a little humor to this equation... Ca(OH)2 is like a big tennis party, where Ca2+ is the star player and OH- is its trusty sidekick. They dissolve together and form a winning team in the water. But the question is, how much of this winning team do we have?

The question tells us that 1.78 grams of Ca(OH)2 dissolves in one liter of water. Let's convert that to moles.

The molar mass of Ca(OH)2 is 74.09 g/mol, so 1.78 grams is approximately 0.024 moles.

Since 1 mole of Ca(OH)2 produces 1 mole of Ca2+ and 2 moles of OH-, we have 0.024 moles of Ca2+ and 0.048 moles of OH-.

Now, let's determine the concentration of Ca2+ and OH- in water. Since we dissolved 0.024 moles of Ca2+ and 0.048 moles of OH- in 1 liter of water, the concentration of each ion is 0.024 M.

Finally, let's calculate the Ksp using the concentrations we just found. The Ksp expression for Ca(OH)2 is:

Ksp = [Ca2+][OH-]^2

Since we have 0.024 M Ca2+ and 0.024 M OH-, we can substitute these values into the Ksp expression:

Ksp = (0.024)(0.024)^2 = 0.000013824 M^3

So, the value of Ksp for Ca(OH)2 is 0.000013824 M^3. With this Ksp value, Ca(OH)2 is ready to win the solubility competition in water and make it rain calcium and hydroxide ions!

To determine the value of Ksp for calcium hydroxide (Ca(OH)2), we need to use the solubility product expression and the concentration of each ion in the solution.

The balanced equation for the dissociation of calcium hydroxide in water is:

Ca(OH)2(s) ↔ Ca2+(aq) + 2OH-(aq)

From the equation, we can see that 1 mole of calcium hydroxide dissociates to give 1 mole of calcium ions (Ca2+) and 2 moles of hydroxide ions (OH-).

Given that the solubility of calcium hydroxide in water is 1.78 g per liter, we can convert this to the molar solubility using the molar mass of calcium hydroxide.

Molar mass of Ca(OH)2 = 40.08 g/mol (Ca) + 2(16.00 g/mol (O)) + 2(1.01 g/mol (H))
= 74.10 g/mol

Now, we can calculate the molar solubility (s) in mol/L:

s = (1.78 g/L) / (74.10 g/mol)
= 0.024 mol/L

Using the solubility product expression, Ksp, which is the product of the concentrations raised to the power of their stoichiometric coefficients, we have:

Ksp = [Ca2+][OH-]^2

Since Ca(OH)2 dissociates to give 1 Ca2+ ion and 2 OH- ions:

Ksp = (s)(2s)^2
= 4s^3

Plugging in the value of the molar solubility (s):

Ksp = 4(0.024 mol/L)^3
≈ 1.38 x 10^-5

Therefore, the value of Ksp for calcium hydroxide (Ca(OH)2) is approximately 1.38 x 10^-5.

To find the value of Ksp (solubility product constant) for calcium hydroxide (Ca(OH)2), we need to use the given information about its solubility in water.

The solubility of Ca(OH)2 is given as 1.78 g per liter. We can use this information to determine the concentration of the dissolved calcium hydroxide in moles per liter (M).

The molar mass of Ca(OH)2 is:
Ca: 40.08 g/mol
O: 16.00 g/mol
H: 1.01 g/mol

Therefore, the molar mass of Ca(OH)2 is:
40.08 + (16.00 x 2) + (1.01 x 2) = 74.16 g/mol

Now, we can calculate the concentration (molarity) of Ca(OH)2 using the given solubility:
1.78 g/L / 74.16 g/mol = 0.024 M

Since the chemical equation for the dissolution of Ca(OH)2 in water is:
Ca(OH)2(s) → Ca2+(aq) + 2OH-(aq)

The solubility product expression for Ca(OH)2 can be written as:
Ksp = [Ca2+][OH-]^2

Since the concentration of Ca2+ ions is equal to the concentration of OH- ions (1:2 ratio), we can write:
Ksp = (0.024)(0.024)^2 = 0.0000144

Hence, the value of Ksp for Ca(OH)2 is approximately 0.0000144.