What is the net ionic equation of the rection between zinc and copper 2 sulfate?
Zn+CuSO4->ZnSO4+Cu (molecular equation) Zn(s)+SO42++Cu2+ -->Cu(s)+Zn2++SO42+(ionic equation) Cu+ Zn(s) --->Cu(s)+Zn(net ionic)
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To determine the net ionic equation for the reaction between zinc (Zn) and copper(II) sulfate (CuSO4), we need to first write the balanced molecular equation and then convert it into the net ionic equation.
Step 1: Write the balanced molecular equation:
The reaction between zinc and copper(II) sulfate can be written as:
Zn + CuSO4 -> ZnSO4 + Cu
In this reaction, zinc (Zn) displaces copper (Cu) from copper(II) sulfate (CuSO4), resulting in the formation of zinc sulfate (ZnSO4) and copper.
Step 2: Convert it into the ionic equation:
In the ionic equation, compounds that are strong electrolytes dissociate into their ions. On the other hand, compounds that are insoluble or weak electrolytes remain intact.
- Zinc (Zn) is a solid and does not dissociate.
- Copper(II) sulfate (CuSO4) dissociates into ions as it is a soluble compound (a strong electrolyte):
CuSO4 (aq) -> Cu2+ (aq) + SO4^2- (aq)
Step 3: Write the net ionic equation:
The net ionic equation includes only the ions that participate in the reaction. In this case, we can eliminate spectator ions (ions that don't undergo any change). The spectator ion in this reaction is sulfate (SO4^2-).
Thus, the net ionic equation for the reaction is:
Zn + Cu2+ -> Zn2+ + Cu
In summary, the net ionic equation for the reaction between zinc and copper(II) sulfate is Zn + Cu2+ -> Zn2+ + Cu.