You need to determine the concentration of a sulfuric acid solution by titration with a standard sodium hydroxide solution. You have a 0.1896 M standard solution. You take a 25.00 mL sample of the original acid solution and dilute it to 250.0 mL. You then take a 10.00 mL sample of the dilute acid solution and titrate it with the standard solution. You need 11.09 mL of the standard solution to reach the endpoint. What is the concentration of the original acid solution?
H2SO4 + 2NaOH ==> 2H2O + Na2SO4
mols NaOH = M x L = 0.1896 x 0.01109 = ?
mols H2SO4 = mols NaOH/2
M H2SO4 = mols H2SO4/L H2SO4. You have mols H2SO4, L H2SO4 = 10 mL(0.010L), solve for M H2SO4. That's the (H2SO4) in the 10 mL. That solution came from 1:10 dilution so the concn of the original is 10x that of the dilute solution.
Oh boy, we're going on a titration adventure! Let's do some calculations and figure out the answer.
First, let's find the moles of sodium hydroxide used in the titration. We have a 0.1896 M standard solution and used 11.09 mL, so:
Moles of NaOH = Molarity × Volume
= 0.1896 M × 0.01109 L
≈ 0.002103 moles
Since the reaction between sulfuric acid (H2SO4) and sodium hydroxide (NaOH) follows a 1:2 ratio, we can say that:
Moles of sulfuric acid = 2 × Moles of NaOH
≈ 2 × 0.002103 mol
≈ 0.004206 mol
Now we can use this to find the concentration of the original acid solution:
Concentration of original acid solution = Moles of acid / Volume of acid
The volume of acid we started with was 10.00 mL, but we diluted it to 250.0 mL. So:
Volume of acid = 10.00 mL × (250.0 mL / 25.00 mL)
= 100.0 mL
Concentration of original acid solution = 0.004206 mol / 0.1000 L
= 0.0421 M
Ta-da! The concentration of the original acid solution is approximately 0.0421 M. Just remember, chemistry can be a bit acidic, but humor helps to neutralize it!
To determine the concentration of the original sulfuric acid solution, we can use the equation:
M1V1 = M2V2
Where:
M1 = concentration of the original acid solution (unknown)
V1 = volume of the original acid solution (25.00 mL)
M2 = concentration of the standard sodium hydroxide solution (0.1896 M)
V2 = volume of the standard sodium hydroxide solution used in the titration (11.09 mL)
First, let's find V1, the volume of the original acid solution, after it was diluted to 250.0 mL:
V1 = (V2 x M2) / M1
Substituting the given values:
25.00 mL = (11.09 mL x 0.1896 M) / M1
Now we can solve for M1, the concentration of the original acid solution:
M1 = (11.09 mL x 0.1896 M) / 25.00 mL
M1 ≈ 0.0836 M
Therefore, the concentration of the original sulfuric acid solution is approximately 0.0836 M.
To determine the concentration of the original sulfuric acid solution, we can use the concept of stoichiometry and the volume of the standard solution required for titration.
First, let's calculate the number of moles of sodium hydroxide (NaOH) used in the titration. From the information given, we know that:
- Volume of NaOH standard solution used: 11.09 mL
- Concentration of NaOH standard solution: 0.1896 M
Since the concentration of the standard solution is given in moles per liter (M), we need to convert the volume used into liters:
11.09 mL = 11.09/1000 = 0.01109 L
Now we can calculate the number of moles of NaOH used in the titration:
moles of NaOH = concentration of NaOH standard solution * volume of NaOH standard solution
= 0.1896 M * 0.01109 L
Next, we need to determine the stoichiometric ratio between NaOH and sulfuric acid (H2SO4). From the balanced equation, we know that the ratio is 1:2.
Therefore, the number of moles of sulfuric acid used is half the number of moles of NaOH:
moles of H2SO4 = (1/2) * moles of NaOH
Now let's consider the dilution of the sulfuric acid solution. We took a 25.00 mL sample, diluted it to 250.0 mL, and then took a 10.00 mL sample for titration.
To find the concentration of the original acid solution, we need to calculate the number of moles of sulfuric acid used in the titration (10.00 mL sample):
moles of H2SO4 in 10 mL = moles of H2SO4 in 25 mL * (10 mL / 25 mL)
= moles of H2SO4 in 25 mL * 0.4
Finally, we can calculate the concentration of the original sulfuric acid solution:
Concentration of original acid solution = moles of H2SO4 in 10 mL / volume of 10 mL sample
Note that the volume used should be in liters:
Concentration of original acid solution = (moles of H2SO4 in 25 mL * 0.4) / (10 mL / 1000)
Performing the calculations, you will get the final concentration of the original sulfuric acid solution.