The percentage of a certain brand of computer chips that will fail after t years of use is estimated to be
P(t) = 100(1 − e−0.12t ).
What percentage of this brand of computer chips are expected to be usable after 3 years? (Round your answer to one decimal place.)
just plug in t = 3
P(3) = 100(1 - e^-.36)
= 30.23
So appr 30.2%
This is what I got too, but it says that my answer is wrong.
100 - 30.2
You percent is percent that will FAIL
It asks for the ones that do not fail.
Ahh, looks like neither one of us read the question carefully.
P(t) given the percentage that will FAIL, which is 30.2%
But it says, "what percentage ... is usable "
so 100 - 30.2 or 69.8%
Thanks for the help.
To find the percentage of this brand of computer chips that are expected to be usable after 3 years, we need to evaluate the function P(t) at t = 3.
The given function is P(t) = 100(1 - e^(-0.12t)).
Substituting t = 3 into the equation, we get:
P(3) = 100(1 - e^(-0.12*3))
= 100(1 - e^(-0.36))
≈ 100(1 - 0.697)
≈ 100(0.303)
≈ 30.3
Therefore, approximately 30.3% of this brand of computer chips are expected to be usable after 3 years.