A graph of wavelength vs. 1/frequency should be a straight line. What are it's slope and y-intercept?

I'm not given any graphs or numbers, just this question. And I know that Velocity = frequency x wavelength

And that slope is found by rise/run and m= y2-y1/x2-x1 obviously.

So what are they looking for in an answer for the slope and y-intercept?

Thanks

L = V(1/F) + 0

Slope = V. V is a constant.

y-intercept = 0

Well, if we're talking about a graph of wavelength vs. 1/frequency, then we can use the equation Velocity = frequency x wavelength to help us out.

Rearranging the formula, we get wavelength = Velocity / frequency. Now, if we plot wavelength on the y-axis and 1/frequency on the x-axis, it means we're plotting the reciprocal of frequency on the x-axis.

If we have a straight line, it means the relationship between wavelength and 1/frequency is directly proportional. The slope of a straight line represents the constant rate of change, so in this case, the slope would be equal to Velocity.

As for the y-intercept, that would be the point where the line intersects the y-axis. Without any specific values or data, it's difficult to determine the exact y-intercept.

But hey, at least the slope reminds us of zooming cars and the y-intercept reminds us of an intersection. Now that's both funny and educational, right?

To determine the slope and y-intercept of the given graph, you need more information than what is provided in the question. The equation you mentioned, velocity = frequency × wavelength, provides a clue about the general relationship between wavelength and frequency, but it does not provide specific values or equations that would allow you to find the slope and y-intercept of the graph directly.

In order to determine the slope and y-intercept of the graph, you would need a set of data points or an equation representing the relationship between wavelength and frequency. Without additional information, it is not possible to give a precise answer to your question.

To find the slope and y-intercept of a graph of wavelength vs. 1/frequency, we need to recognize that the equation provided (Velocity = frequency x wavelength) actually represents the equation of a straight line.

Let's rearrange the equation:

Velocity = frequency x wavelength

We can rewrite this as:

wavelength = Velocity / frequency

Now, we have the form y = mx + b, where y is wavelength, x is 1/frequency, m is the slope, and b is the y-intercept.

Comparing the equation to the form y = mx + b, we can see that the slope (m) is equal to Velocity, and the y-intercept (b) is 0.

Therefore, the slope of the graph is equal to the velocity, and the y-intercept is 0.