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Write the reactions that occur for the benzoic acid/sodium benzoate buffer when you react it with HNO3 and KOH. How would I go about writing it? Thanks.

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  1. Let's call benzoic acid HBz and the benzoate ion then is Bz^-

    With HNO3, the added acid (HNO3) reacts with the base, Bz^-.
    Bz^- + H^+ ==> HBz

    With KOH, the added base (KOH) reacts with the acid, HBz.
    HBz + OH^- ==> Bz^- + H2O

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  2. Thank you so much!!!!

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